Let A,B,C,D,E be n*n matrices, each with non-zero determinant and ABCDE = I, where I = Identity matrix of order n, Then C =

Options :
  1. (B^-1)*(A^-1)*(E^-1)*(D*-1)
  2. (A^-1)*(B^-1)*(D^-1)*(E*-1)
  3. (ABDE)^-1
  4. (EDBA)*-1
Answer and Explanation :-

Answer: Option 1

Explanation:

ABCDE = I BCDE = (A^-1) Pre-Multiplying with A^-1 on both sides CDE = (B^-1)*(A^-1) Pre-Multiplying with B^-1 on both sides CD = (B^-1)*(A^-1)*(E^-1) Post-Multiplying with E^-1 on both sides C = (B^-1)*(A^-1)*(E^-1)*(D^-1) Post-Multiplying with D^-1 on both sides

How do you rate this queston?  Very Easy  Easy  Average  Above Average  Tough

Previous Question : A = a1 a2 a3 b1 b2 b3 c1 c2 c3 Then, a1*cof(b1) + a2*cof(b2) + a3*cof(b3) =

Next Question : If a row or coloumn of a matrix A undergoes transformation given by Ri+kRj or Ci+kCj respectively, t...

Click here for online test on Matrices

Responses


 (Getemail alerts when others member replies)

More available Categories:-








You will be required to do wrong no matter where you go. It is the basic condition of life, to be required to violate your own identity. At some time, every creature which lives must do so. It is the ultimate shadow, the defeat of creation this is the curse at work, the curse that feeds on all life. Everywhere in the universe.
-Philip K. Dick Do Androids Dream of Electric Sheep?