Let A,B,C,D,E be n*n matrices, each with non-zero determinant and ABCDE = I, where I = Identity matrix of order n, Then C =

Options :
  1. (B^-1)*(A^-1)*(E^-1)*(D*-1)
  2. (A^-1)*(B^-1)*(D^-1)*(E*-1)
  3. (ABDE)^-1
  4. (EDBA)*-1
Answer and Explanation :-

Answer: Option 1


ABCDE = I BCDE = (A^-1) Pre-Multiplying with A^-1 on both sides CDE = (B^-1)*(A^-1) Pre-Multiplying with B^-1 on both sides CD = (B^-1)*(A^-1)*(E^-1) Post-Multiplying with E^-1 on both sides C = (B^-1)*(A^-1)*(E^-1)*(D^-1) Post-Multiplying with D^-1 on both sides

How do you rate this queston?  Very Easy  Easy  Average  Above Average  Tough

Previous Question : A = a1 a2 a3 b1 b2 b3 c1 c2 c3 Then, a1*cof(b1) + a2*cof(b2) + a3*cof(b3) =

Next Question : If a row or coloumn of a matrix A undergoes transformation given by Ri+kRj or Ci+kCj respectively, t...

Click here for online test on Matrices


 (Getemail alerts when others member replies)

More available Categories:-

Our physical world seems ready and able to accommodate the needs of the spiritually awakened new Superhuman. The constraints or demands of our material world are not the real problem it is our own spiritual awareness and philosophical wisdom that is lagging behind.
-Anthon St. Maarten Divine Living: The Essential Guide To Your True Destiny