Let A,B,C,D,E be n*n matrices, each with non-zero determinant and ABCDE = I, where I = Identity matrix of order n, Then C =

Options :
  1. (B^-1)*(A^-1)*(E^-1)*(D*-1)
  2. (A^-1)*(B^-1)*(D^-1)*(E*-1)
  3. (ABDE)^-1
  4. (EDBA)*-1
Answer and Explanation :-

Answer: Option 1

Explanation:

ABCDE = I BCDE = (A^-1) Pre-Multiplying with A^-1 on both sides CDE = (B^-1)*(A^-1) Pre-Multiplying with B^-1 on both sides CD = (B^-1)*(A^-1)*(E^-1) Post-Multiplying with E^-1 on both sides C = (B^-1)*(A^-1)*(E^-1)*(D^-1) Post-Multiplying with D^-1 on both sides

How do you rate this queston?  Very Easy  Easy  Average  Above Average  Tough

Previous Question : A = a1 a2 a3 b1 b2 b3 c1 c2 c3 Then, a1*cof(b1) + a2*cof(b2) + a3*cof(b3) =

Next Question : If a row or coloumn of a matrix A undergoes transformation given by Ri+kRj or Ci+kCj respectively, t...

Click here for online test on Matrices

More available Categories:-

Responses


 (Getemail alerts when others member replies)







If pain must come, may it come quickly. Because I have a life to live, and I need to live it in the best way possible. If he has to make a choice, may he make it now. Then I will either wait for him or forget him.
-Paulo Coelho By the River Piedra I Sat Down and Wept