The dehydrohalogenation of neopentyl bromide with alcoholic KOH mainly gives

Options :
  1. 2-methyl-1-butane
  2. 2-methyl-2- butene
  3. 2,2-dimethyl-1-butene
  4. none of the above
Answer and Explanation :-

Answer: Option 2

Explanation:

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Responses


By: Abhinav On: Jan/11/2017

Step1-- first of fall halogen gets removed
Step 2-- methyl shift will occur so as to get more stable intermediate
Step3-- Now according to setzev rule product will form

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